Bitwise AND of Numbers Range
Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.
For example, given the range [5, 7], you should return 4.
Analysis
5: 1 0 1
6: 1 1 0
7: 1 1 1
$: 1 0 0
AND 以后输出左边开始共同的部分。所以这道题是找m和n左边的共同部分输出。 step记录总共移了多少次。m和n每次向右移动一位,直到m和n相等。
Code
public class Solution {
public int rangeBitwiseAnd(int m, int n) {
int step = 0;
while(m != n){
m >>= 1;
n >>= 1;
step++;
}
return m << step;
}
}